Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b) N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;
vector<ll>g[200005];
bool vis[200005];
queue<ll>q_t,q;
bool bfs(int node)
{
q_t.pop();
q.push(node);
vis[node]=true;
while(!q.empty())
{
set<ll>st;
set<ll>::iterator it;
ll cur=q.front(),cnt=0;
q.pop();
for(ll i=0; i<g[cur].size(); i++)
if(vis[g[cur][i]]==false)
{
cnt++;
vis[g[cur][i]]=true;
st.insert(g[cur][i]);
}
while(cnt--)
{
ll piku=q_t.front();
it=st.find(piku);
if(vis[piku]==true && it!=st.end()) q.push(piku),q_t.pop();
else return false;
}
st.clear();
}
return true;
}
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
ll node,a,b,num;
cin>>node;
for(ll i=1; i<node; i++)
{
cin>>a>>b;
g[a].push_back(b);
g[b].push_back(a);
}
for(ll i=1; i<=node; i++) cin>>num,q_t.push(num);
if(bfs(1) && q_t.empty()) cout<<"Yes"<<endl;
else cout<<"No"<<endl;
return 0;
}
///Alhamdulillah
Problem Link: https://codeforces.com/problemset/problem/1037/D
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