Just use the lower bound & check is it greater than the sum or not
Lower bound:https://www.geeksforgeeks.org/upper_bound-and-lower_bound-for-vector-in-cpp-stl/
///Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b) N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;
int main()
{
ll tst,n,q,num;
cin>>tst;
while(tst--)
{
vector<ll>vec;
cin>>n>>q;
ll arr[n+5],sum=0;
for(ll i=0;i<n;i++) cin>>arr[i];
sort(arr,arr+n);
for(ll i=n-1;i>=0;i--) sum+=arr[i],vec.push_back(sum);//cout<<arr[i]<<" "<<sum<<endl;
for(ll i=0;i<q;i++)
{
cin>>num;
ll ans=lower_bound(vec.begin(), vec.end(), num) - vec.begin() + 1;
if(num<=sum) cout<<ans<<endl;
else cout<<"-1"<<endl;
}
}
return 0;
}
///Alhamdulillah
Problem Link:https://codeforces.com/contest/1676/problem/E
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