Skip to main content

AtCoder Beginner Contest 247(D - Cylinder)



 Key:Having knowlwdge about dequeue


///Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh

#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
  angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b)  N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;

int main()
{
    deque< pair<ll,ll> >dq;
    ll tst,num,c,x;
    cin>>tst;
    while(tst--)
    {
        cin>>num;
        if(num==1)
        {
            cin>>x>>c;
            dq.push_back(make_pair(c,x));
        }
        else
        {
            cin>>c;
            ll cnt=0;
            while(dq.size()>0 && c!=0)
            {
                if(c>=dq.front().first)
                {
                    cnt+=(dq.front().first*dq.front().second);
                    c-=dq.front().first;
                    dq.pop_front();
                }
                else
                {
                    cnt+=(c*dq.front().second);
                    ll a=dq.front().first-c;
                    ll b=dq.front().second;
                    dq.pop_front(),c=0;
                    dq.push_front(make_pair(a,b));
                }
            }
            cout<<cnt<<endl;
        }
    }
    return 0;
}
///Alhamdulillah

Problem link:https://atcoder.jp/contests/abc247/tasks/abc247_d
Labels:

Comments

Post a Comment

Popular posts from this blog

Codeforces round 1676(A. Lucky?)

Just count the  first three  &  last three  number ///Bismillahir Rahmanir Rahim ///Author: Tanvir Ahmmad ///CSE,Islamic University,Bangladesh #include< iostream > #include< cstdio > #include< algorithm > #include< string > #include< cstring > #include< sstream > #include< cmath > #include< cstring > #include< vector > #include< queue > #include< map > #include< set > #include< stack > #include< vector > #include< iterator > #include   < functional >   ///sort(arr,arr+n,greater<int>()) for decrement of array /*every external angle sum=360 degree   angle find using polygon hand(n) ((n-2)*180)/n*/ ///Floor[Log(b)  N] + 1 = the number of digits when any number is repres...
Post a Comment
Read more

Codeforces round 1661(B. Getting Zero)

using   second operation  the answer is maximum is  15  because  2 15 =32768 so we need to  pre-calculate all the illegible input 0 to 32768   using  second operation Then  just increment 1(using first operation)  from input check is it  minimum is not ! ///Bismillahir Rahmanir Rahim ///Author: Tanvir Ahmmad ///CSE,Islamic University,Bangladesh #include< iostream > #include< cstdio > #include< algorithm > #include< string > #include< cstring > #include< sstream > #include< cmath > #include< cstring > #include< vector > #include< queue > #include< map > #include< set > #include< stack > #include< vector > #include< iterator > #include   < functional >   ///sort(arr,arr+n,greater<int...
Post a Comment
Read more

Codeforces round 1676(E. Eating Queries)

Just use the lower bound & check is it greater than the sum or not Lower bound:https://www.geeksforgeeks.org/upper_bound-and-lower_bound- for -vector- in -cpp-stl/ ///Bismillahir Rahmanir Rahim ///Author: Tanvir Ahmmad ///CSE,Islamic University,Bangladesh #include< iostream > #include< cstdio > #include< algorithm > #include< string > #include< cstring > #include< sstream > #include< cmath > #include< cstring > #include< vector > #include< queue > #include< map > #include< set > #include< stack > #include< vector > #include< iterator > #include   < functional >   ///sort(arr,arr+n,greater<int>()) for decrement of array /*every external angle sum=360 degree   angle find using polygon hand(n) ((n-2)*180...
Post a Comment
Read more