Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b) N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;
int fx[]= {1,-1,0,0};
int fy[]= {0,0,-1,1};
const ll N=1e6+9;
vector<ll> graph[N];
bool vis[N];
stack<ll>stk;
void dfs(ll node)
{
vis[node]=true;
for(ll i=0; i<graph[node].size(); i++)
if(vis[graph[node][i]]==false)
dfs(graph[node][i]);
stk.push(node);
}
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
ll node,op,p,ans[N];
cin>>node>>op;
for(ll i=1; i<=node; i++)
ans[i]=1;
for(ll i=1; i<=op; i++)
{
cin>>p;
ll arr[p+9];
for(ll j=0; j<p; j++)
cin>>arr[j];
for(ll j=1; j<p; j++)
graph[arr[j]].push_back(arr[j-1]),graph[arr[j-1]].push_back(arr[j]);
}
for(ll i=1; i<=node; i++)
if(vis[i]==false)
{
dfs(i);
ll sz=stk.size();
while(!stk.empty())
{
ll num=stk.top();
ans[num]=sz;
stk.pop();
}
}
for(ll i=1; i<=node; i++)
cout<<ans[i]<<" ";
cout<<endl;
return 0;
}
///Alhamdulillah
Problem Link:https://codeforces.com/problemset/problem/1167/C
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