Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b) N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;
int fx[]= {1,-1,0,0};
int fy[]= {0,0,-1,1};
const ll N=1e5+9;
vector<ll> graph[N];
ll store[N];
bool vis[N];
ll bfs(ll node)
{
queue<ll>q;
ll cost=store[node];
vis[node]=true;
q.push(node);
while(!q.empty())
{
ll fro=q.front();
q.pop();
for(ll i=0; i<graph[fro].size(); i++)
if(vis[graph[fro][i]]==false)
{
vis[graph[fro][i]]=true;
cost=min(cost,store[graph[fro][i]]);
q.push(graph[fro][i]);
}
}
return cost;
}
int main()
{
ll node,edge,a,b,sum=0;
cin>>node>>edge;
for(ll i=1; i<=node; i++)
cin>>store[i];
for(ll i=1; i<=edge; i++)
{
cin>>a>>b;
graph[a].push_back(b);
graph[b].push_back(a);
}
for(ll i=1; i<=node; i++)
if(vis[i]==false)
sum+=bfs(i);
cout<<sum<<endl;
return 0;
}
///Alhamdulillah
Problem Link:https://codeforces.com/problemset/problem/893/C
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