Bismillahir Rahmanir Rahim
Thinking like a CUP_CAKE:
Example 1: 1 8 9 whatever we will do output is still NO
Example 2: 0 8 9 first mod 9 then mod 8 after that 0 0 0.So output is YES
Example 3: 1 5 8 first mod 7 then mod 4 after that 1 1 1.So output is YES
Example 4: 0 5 8 first mod 8 then mod 5 after that 0 0 0.So output is YES
Only the consecutively elements & 1 remaining makes the output of this array's output NO.
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b) N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;
int main()
{
ll tst,n;
cin>>tst;
while(tst--)
{
cin>>n;
ll arr[n+7];
bool por_por=false,blow=false;
for(ll i=1;i<=n;i++) cin>>arr[i];
sort(arr+1,arr+n+1);
for(ll i=1;i<=n;i++)
{
if(arr[i]==1) blow=true;
if(i<n && arr[i+1]-arr[i]==1) por_por=true;
}
if(blow && por_por) cout<<"NO"<<endl;
else cout<<"YES"<<endl;
}
return 0;
}
///Alhamdulillah
Problem Link: https://codeforces.com/problemset/problem/1656/C
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