Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b) N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;
ll mod=1000000007;
ll dx[] = { -2, -1, 1, 2, -2, -1, 1, 2 };
ll dy[] = { -1, -2, -2, -1, 1, 2, 2, 1 };
int main()
{
ll tst,n;
cin>>tst;
while(tst--)
{
vector< pair<ll,ll> >vec;
vector<ll>v;
cin>>n;
ll arr[n+9];
for(ll i=1;i<=n;i++)
{
cin>>arr[i];
if(arr[i]<i) vec.push_back(make_pair(arr[i],i)),v.push_back(arr[i]);
}
sort(vec.begin(),vec.end());
sort(v.begin(),v.end());
ll sz=vec.size(),sum=0,up;
for(ll i=0;i<vec.size();i++)
up=((upper_bound(v.begin(), v.end(), vec[i].second)) - v.begin() + 1),sum+=(sz-up+1);
cout<<sum<<endl;
}
return 0;
}
///Alhamdulillah
Problem Link:https://codeforces.com/problemset/problem/1703/F
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