Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b) N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;
int main()
{
map<string,ll>mp;
map<string,ll>::iterator it;
vector<string>vec[109];
ll n,k=0,flag=0;
cin>>n;
string str[n+2],ans[n+2];
for(ll i=0; i<n; i++) cin>>str[i];
for(ll i=1; i<=109; i++)
for(ll j=0; j<n; j++)
if(str[j].size()==i)
ans[k++]=str[j];
if(k==n)
{
for(ll i=0; i<k-1; i++)
{
string a=ans[i],b=ans[i+1];
ll cnt=0;
for(ll j=0; j<b.size(); j++)
{
if(b[j]==a[0])
{
for(ll k=0,l=j; k<a.size(); k++,l++)
{
if(b[l]==a[k])
cnt++;
else break;
}
}
if(cnt==a.size())
{
flag++;
break;
}
else cnt=0;
}
}
if(flag==(n-1))
{
cout<<"YES"<<endl;
for(ll i=0; i<n; i++)
cout<<ans[i]<<endl;
}
else cout<<"NO"<<endl;
}
else
cout<<"NO"<<endl;
return 0;
}
///Alhamdulillah
Problem Link: https://codeforces.com/contest/988/problem/B
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