Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b) N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;
int main()
{
ll n,tst,ca=1;
cin>>tst;
while(tst--)
{
cin>>n;
ll arr[n+6],ans[n+6],pos=1,flag=0;
for(ll i=1; i<=n; i++)
cin>>arr[i];
sort(arr+1,arr+(n+1));
if(n%2==1)
for(ll i=1; i<=(n/2)+1; i++)
ans[pos++]=arr[i],ans[pos++]=arr[i+(n/2)+1];
else
for(ll i=1; i<=(n/2); i++)
ans[pos++]=arr[i],ans[pos++]=arr[i+(n/2)];
ans[0]=ans[n],ans[n+1]=ans[1];///making neighbour for cycle
for(ll i=1; i<=n; i++)
if((ans[i-1]<=ans[i] && ans[i]<=ans[i+1]) || (ans[i-1]>=ans[i] && ans[i]>=ans[i+1]))
{
flag=1;
break;
}
if(flag)
cout<<"NO"<<endl;
else
{
cout<<"YES"<<endl;
for(ll i=1; i<=n; i++)
cout<<ans[i]<<" ";
cout<<endl;
}
}
return 0;
}
///Alhamdulillah
Problem Link:https://codeforces.com/problemset/problem/1686/C
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