Skip to main content

Codeforces round 1684(C. Column Swapping)

first check than than we just need to swap one column with another or not.
If we need to swap 2 or 0 column then just swap & feel that Accepted...
Else feel disappoint & carried out (-1).

///Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh

#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
  angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b)  N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;

int main()
{
    ll n,m,tst;
    cin>>tst;
    while(tst--)
    {
        cin>>n>>m;
        ll arr[n+3][m+2],sorted[n+3][m+2],flag=0,k=0,ans[9];
        for(ll i=0; i<n; i++)
            for(ll j=0; j<m; j++)
                cin>>arr[i][j],sorted[i][j]=arr[i][j];
        for(ll i=0; i<n; i++)
            sort(sorted[i],sorted[i]+m);

            set<ll>st;
            set<ll>::iterator it;
        for(ll i=0; i<n; i++)
            for(ll j=0; j<m; j++)
                if(sorted[i][j]!=arr[i][j])
                    st.insert(j);
        if(st.size()==0) cout<<"1 1"<<endl;
        else if(st.size()==2)
        {
            it=st.begin();
            while(it!=st.end())
            {
                ans[k++]=*it;
                it++;
            }
            for(ll i=0; i<n; i++)
                swap(arr[i][ans[0]],arr[i][ans[1]]);
            for(ll i=0; i<n; i++)
                for(ll j=0; j<m; j++)
                    if(sorted[i][j]!=arr[i][j])
                        flag=1;
            if(flag)
                cout<<"-1"<<endl;
            else
                cout<<ans[0]+1<<" "<<ans[1]+1<<endl;
        }
        else
            cout<<"-1"<<endl;
    }
    return 0;
}
///Alhamdulillah
 
Problem Link:https://codeforces.com/problemset/problem/1684/C


 

Comments

Popular posts from this blog

Codeforces round 1661(B. Getting Zero)

using   second operation  the answer is maximum is  15  because  2 15 =32768 so we need to  pre-calculate all the illegible input 0 to 32768   using  second operation Then  just increment 1(using first operation)  from input check is it  minimum is not ! ///Bismillahir Rahmanir Rahim ///Author: Tanvir Ahmmad ///CSE,Islamic University,Bangladesh #include< iostream > #include< cstdio > #include< algorithm > #include< string > #include< cstring > #include< sstream > #include< cmath > #include< cstring > #include< vector > #include< queue > #include< map > #include< set > #include< stack > #include< vector > #include< iterator > #include   < functional >   ///sort(arr,arr+n,greater<int...

Codeforces round 1676(A. Lucky?)

Just count the  first three  &  last three  number ///Bismillahir Rahmanir Rahim ///Author: Tanvir Ahmmad ///CSE,Islamic University,Bangladesh #include< iostream > #include< cstdio > #include< algorithm > #include< string > #include< cstring > #include< sstream > #include< cmath > #include< cstring > #include< vector > #include< queue > #include< map > #include< set > #include< stack > #include< vector > #include< iterator > #include   < functional >   ///sort(arr,arr+n,greater<int>()) for decrement of array /*every external angle sum=360 degree   angle find using polygon hand(n) ((n-2)*180)/n*/ ///Floor[Log(b)  N] + 1 = the number of digits when any number is repres...

Codeforces Round #282 (Div. 2) (B. Modular Equations)

Bismillahir Rahmanir Rahim ///Author: Tanvir Ahmmad ///CSE,Islamic University,Bangladesh #include< iostream > #include< cstdio > #include< algorithm > #include< string > #include< cstring > #include< sstream > #include< cmath > #include< cstring > #include< vector > #include< queue > #include< map > #include< set > #include< stack > #include< vector > #include< iterator > #include   < functional >   ///sort(arr,arr+n,greater<int>()) for decrement of array /*every external angle sum=360 degree   angle find using polygon hand(n) ((n-2)*180)/n*/ ///Floor[Log(b)  N] + 1 = the number of digits when any number is represented in base b using   namespace  std; typedef   long   long ...