first check than than we just need to swap one column with another or not.
If we need to swap 2 or 0 column then just swap & feel that Accepted...
Else feel disappoint & carried out (-1).
///Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b) N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;
int main()
{
ll n,m,tst;
cin>>tst;
while(tst--)
{
cin>>n>>m;
ll arr[n+3][m+2],sorted[n+3][m+2],flag=0,k=0,ans[9];
for(ll i=0; i<n; i++)
for(ll j=0; j<m; j++)
cin>>arr[i][j],sorted[i][j]=arr[i][j];
for(ll i=0; i<n; i++)
sort(sorted[i],sorted[i]+m);
set<ll>st;
set<ll>::iterator it;
for(ll i=0; i<n; i++)
for(ll j=0; j<m; j++)
if(sorted[i][j]!=arr[i][j])
st.insert(j);
if(st.size()==0) cout<<"1 1"<<endl;
else if(st.size()==2)
{
it=st.begin();
while(it!=st.end())
{
ans[k++]=*it;
it++;
}
for(ll i=0; i<n; i++)
swap(arr[i][ans[0]],arr[i][ans[1]]);
for(ll i=0; i<n; i++)
for(ll j=0; j<m; j++)
if(sorted[i][j]!=arr[i][j])
flag=1;
if(flag)
cout<<"-1"<<endl;
else
cout<<ans[0]+1<<" "<<ans[1]+1<<endl;
}
else
cout<<"-1"<<endl;
}
return 0;
}
///Alhamdulillah
Problem Link:https://codeforces.com/problemset/problem/1684/C
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