Skip to main content

Codeforces round 1059(B. Forgery)


///Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh

#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
  angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b)  N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;

int main()
{
    ll n,m,flag=1;
    cin>>n>>m;
    string str[n+9],new_str[n+9];
    char rplc='#';



    for(ll i=0; i<n; i++)
        for(ll j=0; j<m; j++)
            new_str[i].append(".");
    for(ll i=0; i<n; i++)
        cin>>str[i];

    for(ll i=1; i<n-1; i++)
        for(ll j=1; j<m-1; j++)
            if(str[i-1][j-1]=='#' && str[i-1][j]=='#' && str[i-1][j+1]=='#' && str[i][j-1]=='#'  && str[i][j+1]=='#' && str[i+1][j-1]=='#' && str[i+1][j]=='#' && str[i+1][j+1]=='#')
            {
                new_str[i-1][j-1] = rplc;
                new_str[i-1][j] = rplc;
                new_str[i-1][j+1] = rplc;

                new_str[i][j-1] = rplc;
                new_str[i][j+1] = rplc;

                new_str[i+1][j-1] = rplc;
                new_str[i+1][j] = rplc;
                new_str[i+1][j+1] = rplc;
            }
    for(ll i=0; i<n; i++)
        for(ll j=0; j<m; j++)
            if(str[i][j]!=new_str[i][j])
                flag=0;

    if(flag==1)
        cout<<"YES"<<endl;
    else
        cout<<"NO"<<endl;
    return 0;
}
///Alhamdulillah

Problem link:https://codeforces.com/problemset/problem/1059/B

 

Comments

Popular posts from this blog

Codeforces round 1661(B. Getting Zero)

using   second operation  the answer is maximum is  15  because  2 15 =32768 so we need to  pre-calculate all the illegible input 0 to 32768   using  second operation Then  just increment 1(using first operation)  from input check is it  minimum is not ! ///Bismillahir Rahmanir Rahim ///Author: Tanvir Ahmmad ///CSE,Islamic University,Bangladesh #include< iostream > #include< cstdio > #include< algorithm > #include< string > #include< cstring > #include< sstream > #include< cmath > #include< cstring > #include< vector > #include< queue > #include< map > #include< set > #include< stack > #include< vector > #include< iterator > #include   < functional >   ///sort(arr,arr+n,greater<int...

Codeforces round 1676(A. Lucky?)

Just count the  first three  &  last three  number ///Bismillahir Rahmanir Rahim ///Author: Tanvir Ahmmad ///CSE,Islamic University,Bangladesh #include< iostream > #include< cstdio > #include< algorithm > #include< string > #include< cstring > #include< sstream > #include< cmath > #include< cstring > #include< vector > #include< queue > #include< map > #include< set > #include< stack > #include< vector > #include< iterator > #include   < functional >   ///sort(arr,arr+n,greater<int>()) for decrement of array /*every external angle sum=360 degree   angle find using polygon hand(n) ((n-2)*180)/n*/ ///Floor[Log(b)  N] + 1 = the number of digits when any number is repres...

Codeforces Round #282 (Div. 2) (B. Modular Equations)

Bismillahir Rahmanir Rahim ///Author: Tanvir Ahmmad ///CSE,Islamic University,Bangladesh #include< iostream > #include< cstdio > #include< algorithm > #include< string > #include< cstring > #include< sstream > #include< cmath > #include< cstring > #include< vector > #include< queue > #include< map > #include< set > #include< stack > #include< vector > #include< iterator > #include   < functional >   ///sort(arr,arr+n,greater<int>()) for decrement of array /*every external angle sum=360 degree   angle find using polygon hand(n) ((n-2)*180)/n*/ ///Floor[Log(b)  N] + 1 = the number of digits when any number is represented in base b using   namespace  std; typedef   long   long ...