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Codeforces round 1030(C. Vasya and Golden Ticket)


 first sum the string then divide it & check

   Example:530178 sum=24
   so it can divided into 2,3,4,6,8,12(these can be substring sum)
   if we get any of these then it will be YES
   5 3 0 =8
   1 7    =8
   8      =8
Some thinkable cases:0 0 0 
                     1 1 1 1 1
                     2 2 
Otherwise NO

///Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh

#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
  angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b)  N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;

int main()
{
    ll n,sum=0,flag=0;
    string str;
    set<ll>st;
    set<ll>::iterator it;
    map<ll,ll>mp;
    cin>>n>>str;
    for(ll i=0;i<str.size();i++)
    {
        if(mp.find(str[i]-48)==mp.end()) mp[str[i]-48]=1;
        else mp[str[i]-48]++;
    }
    for(ll i=0; i<str.size(); i++)
        sum+=(str[i]-48);
    for(ll i=1; i<=sqrt(sum); i++)
        if(sum%i==0)
            st.insert(i),st.insert(sum/i);
    for(it=st.begin(); it!=st.end() && flag==0; it++)
    {
        ll num=*it,ofsec=0,cnt=0;
        for(ll i=0; i<str.size(); i++)
        {
            ofsec+=(str[i]-48);
            if(ofsec==num)
                cnt++,ofsec=0;
            if(ofsec>num)
                break;
            if(i==(str.size()-1) && (sum/num)==cnt && cnt!=1)
            {
                flag=1;
                break;
            }
        }
    }
    if(flag || mp.size()==1) cout<<"YES"<<endl;
    else cout<<"NO"<<endl;
    return 0;
}
///Alhamdulillah

Problem link:https://codeforces.com/contest/1030/problem/C

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