There are three cases:
A.There have a gcd of two number(a,b) answer will be 0
B.Need increament one of the number (a+1,b)/(a,b+1) answer will be 1
C.Increament both number answer will be 2
///Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b) N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;
ll solve(ll a,ll b)
{
if(__gcd(a,b)!=1)
return 0;
if( __gcd(a+1,b)!=1)
return 1;
else if( __gcd(b+1,a)!=1)
return 1;
else
return 2;
}
int main()
{
ll tst,a,b;
cin>>tst;
while(tst--)
{
cin>>a>>b;
cout<<solve(a,b)<<endl;
}
return 0;
}
///Alhamdulillah
problem link:https://www.codechef.com/LP2TO307/problems/CHFGCD
Comments
Post a Comment