There are three case
1.Equal day
2.Alice 1 day greater than Bob
3.Bob 1 day greater than Alice
///Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b) N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;
int main()
{
ll tst,a,b,p,q;
cin>>tst;
while(tst--)
{
cin>>a>>b>>p>>q;
if(p%a==0 && q%b==0)
{
ll alice=ceil(p/a);
ll bob=ceil(q/b);
if(abs(alice-bob)<=1)
cout<<"YES"<<endl;
else
cout<<"NO"<<endl;
}
else
cout<<"NO"<<endl;
}
return 0;
}
///Alhamdulillah
problem link:https://www.codechef.com/LP2TO307/problems/ALTER
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