Light OJ -- 1053(Higher

Light OJ -- 1053(Higher_math)

Check weather it is right angle or not. Using the Pythagoras' theorem.

///Bismillahir Rahmanir Rahim
///Author: Tanvir Ahmmad
///CSE,Islamic University,Bangladesh
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<string>
#include<cstring>
#include<sstream>
#include<cmath>
#include<bitset>
#include<cstring>
#include<vector>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<vector>
#include<iterator>
#include <functional> ///sort(arr,arr+n,greater<int>()) for decrement of array
/*every external angle sum=360 degree
  angle find using polygon hand(n) ((n-2)*180)/n*/
///Floor[Log(b)  N] + 1 = the number of digits when any number is represented in base b
using namespace std;
typedef long long ll;
typedef long long unsigned llu;
int main()
{
    ll tst,arr[5];
    scanf("%d",&tst);
    for(int i=1; i<=tst; i++)
    {
        cin>>arr[0]>>arr[1]>>arr[2];
        sort(arr,arr+3);
        if((arr[0]*arr[0])+(arr[1]*arr[1])==(arr[2]*arr[2])) printf("Case %d: yes\n",i);
        else printf("Case %d: no\n",i);
    }
    return 0;
}
///Alhamdulillah

Problem Link:https://lightoj.com/problem/higher-math

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